Im new to the techniques of EV Training, and I want to know how many EVs you can actually get per wild Pokemon battle.
Heres my question:
If my Mewtwo is holding Power Lens (+4 Sp.Atk EVs) and I defeat a Golduck (+2 Sp.Atk EVs) while Mewtwo has Pokerus, how many EV's will I be awarded at the end of the battle?
Basically, how would all of that be added up?
Power Lens = +4
Golduck EV's = +2
Pokerus = x2
Do I have the right concept, or am I adding up something wrong? (Do I have any of it right? Im new, I just want this cleared up before I actually start EV training my Mewtwo.)
Mod Edit: Aye, you can have this moved. However, please do not double post, use the Edit button instead.
Mon Jun 11, 2007 4:25 pm
Joined: Thu May 03, 2007 7:40 pm Posts: 99 Location: Training with my Charizard.
Yes, you did the right math there, so in other words your right
Tue Jun 12, 2007 7:58 am
Joined: Thu May 10, 2007 9:27 am Posts: 186
And, to my knowledge, the EVs obtained before pokerus are unaffected.
Joined: Sat Jun 09, 2007 2:17 pm Posts: 13 Location: Obviously, somewhere.
Nah, it's 4 EV's added onto the 1 or 2 you already gained. So fighting a Gyarados with a Power Brace equipped would be 2 Attack EV's + 4 from the Brace. And then the Pokerus bonus is multiplied, meaning 6 x 2, equalling a whopping 12 EV's from one fight.
Man, Diamond and Pearl made it real easy to EV train.
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